## Which side of a line does a point lie?

That is whether the Point lies to the Right of Line Segment or to the Left of Line Segment. The point might lie behind the line segment, in that case we assume imaginary line by extending the line segment and determine the direction of point.

## Is point on right side of line?

2 Answers By Expert Tutors Standard form: y = mx + b. Let’s call this point 4, with coordinates (x3,y4). If y3 – y4 > 0, then point 3 lies above the line (to the “left”). If y3 – y4 < 0, then point 3 lies below the line (to the “right”).

## How do you determine if a point is on a line segment?

Use the point slope formula to check if the point is on the line segment

1. pt1 = (0,0)
2. pt2 = (5,5)
3. pt3 = (2,2)
4. x1, x2, x3 = pt1[0], pt2[0], pt3[0]
5. y1, y2, y3 = pt1[1], pt2[1], pt3[1]
6. slope = (y2 – y1) / (x2 – x1)
7. pt3_on = (y3 – y1) == slope * (x3 – x1)

## How do you check if a point lies between two points?

The simplest is as follows.

1. if (x-x1)/(x2-x1) = (y-y1)/(y2-y1) = alpha (a constant), then the point C(x,y) will lie on the line between pts 1 & 2.
2. If alpha < 0.0, then C is exterior to point 1.
3. If alpha > 1.0, then C is exterior to point 2.
4. Finally if alpha = [0,1.0], then C is interior to 1 & 2.

## Is there a point between two points?

Sometimes you need to find the point that is exactly between two other points. This middle point is called the “midpoint”. By definition, a midpoint of a line segment is the point on that line segment that divides the segment in two congruent segments.

## How do you calculate work problems?

To solve a work word problem, multiply the hourly rate of the two people working together by the time spent working to get the total amount of time spent on the job. Knowledge of solving systems of equations is necessary to solve these types of problems.

## What is the relation between work and time?

Work Done = Time Taken × Rate of Work. Rate of Work = 1 / Time Taken. Time Taken = 1 / Rate of Work. If a piece of work is done in x number of days, then the work done in one day = 1/x.