## How many combinations of 3 numbers are there in 6 numbers?

There are, you see, 3 x 2 x 1 = 6 possible ways of arranging the three digits. Therefore in that set of 720 possibilities, each unique combination of three digits is represented 6 times. So we just divide by 6. 720 / 6 = 120.

## How many possible 4 digit combinations are there?

10,000 possible combinations

## How many 4 digit numbers can be formed using 4 numbers?

Therefore, there are 360 – 72 = 288(Option C) numbers possible such that 2 and 5 don’t come together. There are 6 digits in total and we have to form a 4 digit number, hence that can be done in 6p4 ways. The total number of 4 digit numbers possible without repetition are 6!/2!= 360.

## How many 4 digit numbers can be formed by using the digits 3 4 9 and 0 without repeating any digit?

Answer. 120 combinations can be formed.

## How many 4 digit number can be formed by using the digits 1 to 9 if repetition of digit is not allowed?

For the first digit place there are 9 options , second digit place there are 8 options, third digit place there are 7 options and fourth digit place there are 6 options.

## How many four digit numbers can be formed from the digits 1234 with repetition?

Thus if you are not allowed to repeat a digit the number of possible 4 digit numbers you can construct from 1,2,3,4 is 4 3 2 1 = 24.

## How many 4-digit numbers can be formed from the digits 12345 which are divisible by 3?

Hence the units place can be filled in ‘2’ ways. Therefore, the number of 4 digited numbers divisible by 3. =63×2=216×2=432.

## How many three digit numbers can be formed using digits 0 to 9 if repetition is allowed?

How many 3-digit numbers can be formed by using the digits 1 to 9 if no digit is repeated? Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams. Therefore, total numbers =89×8×7504.

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